Neco 2022 Chemistry Questions and Answers





(i) Base has bitter taste
(ii) Base is soapy to touch
(iii) Base turns litmus paper blue

The steps involved are:
(i)Shift conversion
(ii)Removal of carbon (iv) oxide
(iii)Steam reforming

Cracking is the process by which heavier hydrocarbon molecule is splitted into two or more lighter molecules

Thermal cracking

P ion = 1s²2s²2p⁶

Formula of chloride is Pcl2

Reducing agent
This is because it undergoes oxidation by losing electrons

Electron affinity is the energy released when a gaseous atom gains an electron to form a gaseous negative ion.

This is because it has lone pairs of electrons

(i) By adding a catalyst

(ii) FeS(s) + 2HCl(g) —–> FeCl(g) + H2S(s)

Xg = ?
No. of FeCl2 = 127g/mole
No. of FeS= 88g/mole

Mole = Mass/ No. of Mass = 3.2/127 = 0.025mole of FeCl2

By comparison,
1 mole of FeS = 1 mole of FeCl2
X moles of FeS = 0.025 of FeCl2
X = 0.025mole of FeS

Mass = Mole * molar mass
Mass = 0.025*88
Mass = 2.2g of FeS
X = 2.2g



(2ai) Three postulates of kinetic theory of gasses
(i) gas molecules move randomly in straight lines
(ii) the collisions of gas molecules are perfectly elastic
(iii) the coercive forces between the gas molecules and negligible

Solubility in water easily liquefies

Copper, iron, aluminum, Magnesium


(i) activation energy is the minimum amount of energy possesses by colliding reactants particles for reaction to occur
(ii) catalyst lowers the activation energy
(iii) finely divided nickel
(iv) Sodium trioxocarbonate (iv) (Na2CO3) and Water (H2O)

(i) it reacts with alkanols to form esters
(ii) It Liberates Carbon(iv) Oxide to form trioxocarbonate (iv)

(i) I.2KI(aq) + Cl2(g) ––> 2KCl2(g) + I(s)
(ii) Zn(s) + Cl2(g) ––> ZnCl2(s)

Cl2 + 2NaOH ––> NaCl + H2O + Q
Q is sodium Trioxochlorate(v)

Covalent bond

(i) Butane
(ii) Propene
(iii) Ethanol
(iv) Ethyne


(i) Iron (Fe)
(ii) Fe3C4
– chlorine displace bromine
– The displaced bromine gives the reddish brown colour
(iv) 2KBr(aq) + Cl2(g) —-> 2KCl(aq) + Br2(l)

– Cement industries
– Glass industries
(ii) Quick lime
=>Salt to be prepared<=
– KNO3
– CaCl2
– FeCl3
– CuSO4
– PbSO4

=>Starting material<=
– CaCO3
– Fe(s)
– CuO
– Pb(NO3)2

=>Method of preparation<=
– Neutralization
– Dilute acid and trioxocarbonate (iv)
– Combination of constituent elements
– Dilute acid and insoluble base
– Double decomposition

(i) By burning sulphur in dry air
(ii) 2SO2(aq) + O2(g) ——> 2SO3(aq) + heat

– Combining sulphur (iv) oxide with oxygen in excess to firm sulphur (vi) oxide
– Cooling and passing the SO3 formed through and absorption tower to produce the acid

(i) 2*9600C produces 119g
(1.5*2*3600)C produces xg
x= 1.5*2*3600*119/2*96500
x= 6.66grams

(ii) Strong electrolyte conducts large currents WHILE Weak electrolyte do not conduct electricity readily


(i) this is the heat evolved when one mole of the substance is Burned completely and oxygen under standard conditions
(ii) isomerism is a phenomenon where two or more compounds has the same molecular formula but different structures

(i) acidic = NO2
Neutral = CO
basic = Fe2O3
Amphoteric = Al2O3

(i) nitrous oxide
(ii) carbon (iv) oxide

Fractional distillation of liquid air

2KNO3 —> 2KNO2(s) + O2(g)
(NH4)2 (CO)3 —> 2NH3(g) + CO2(g) + H2O(g)

No of molecules=4/16 × 6.02 × 10²³
=1.51 × 10²³

I W = Carbon(iv) Oxide
II Carbon
(iii) I Hydration
III Oxidation


Gay Lussac states that when gases react, they do so in volume which bears a simple whole-number ratio to one another and the volume of their products.

2CO + O2 —-> 2CO2
2 1 2
100cm³ 70cm³ 100cm³

Total volume = 100+70+100 = 270cm³

(i)It is used in the production of other chemical substances
(ii)It is used as a drying or dehydrating agent

(i) ZnCO3 —–> ZnO + CO2

– High temperature
– High pressure

(ii) ZnO + H2SO4 —-> ZnSO4 + H2

– Catalyst
– Surface area

(i) Crystallization method
(ii) By heating the ZnSO4 with an alkali metal carbonate

(i) This is due to the presence of extra electrons not used for bonding graphite
(ii) This is because sodium salts are soluble and double decomposition is used for the production of insoluble salts
(iii) It is an alkali substance ie possesses basic properties

(i)Bitumen coal
(ii)Peat coal

Fractional distillation



Vanadium (v) oxide : It enables equilibrium equilibrium to be reached in a shorter time

(i) Caustic soda solution
(ii) Pure Alumina in molten cryolite
(iii) Graphite rods: Oxygen is given off at the anode, slowing burning away the anode as CO2

– Dilute acids have a sour taste
– Acids turn blue litmus red
– Concentrated forms of strong acids are corrosive

(ii) HCl will have a larger electrical conductivity because it ionizes completely in water to give hydrogen ions with concentration very high

(i) As an acid with bases
NaCl(aq) + HNO3(aq) —> NaNO3(aq) + H2O(l)

(ii) H2S(g) + 2HNO3(aq) —-> S(s) + 2H2O(l) + 2NO2(g)



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